In the arrangement shown in figure wedge of mass M moves towards left with an acceleration a. All surfaces are smooth. The acceleration of mass m relative to wedge is –
A
a/2
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
Let acceleration of mass m relative to wedge down the plane is a r . Its absolute acceleration in horizontal direction is a r cos 60° – a (towards right). Hence, let N be the normal reaction between the mass and the wedge. Then
N sin θ = Ma = m (a r cos 60° – a)
or ar = 
= 
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