Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A man is standing on a weighing machine placed in a lift. When Stationary, his weight is recorded as 40 kg. If the lift is moved upwards with an acceleration of 2 ms –2 , then the weight recorded in the machine will be -(g = 10 ms –2 )
Text Solution
Verified by ExpertsThe correct answer is:
D
N = m (g + a) or N = 40 (10 + 2)
or N = 480 newton or N = 48 kg - wt.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A vessel containing water is given a constant acceleration a towards the right, along a straight ho…
A ship of mass \(3 \times 10^{7} \, \text{kg}\) initially at rest is pulled by a force of \(5 \time…
The mass of a body measured by a physical balance in a lift at rest is found to be m. If the lift i…
Three weights W, 2W and 3W are connected to identical springs suspended from a rigid horizontal rod…
When forces F_1, F_2, F_3 are acting on a particle of mass m such that F_2 and F_3 are mutually per…
The spring balance A reads 2 kg with a block m suspended from it. A balance B reads 5 kg when a bea…