Home Physics Newton's Laws of Motion Mix Two skaters A and B of masses 50 kg and 70 k…
Physics Newton's Laws of Motion Mix MCQ (Single Correct)

Two skaters A and B of masses 50 kg and 70 kg respectively stand facing each other 6 m apart. Then they pull on a rope stretched between them. How far has each moved when they meet –

A
Both have moved 3 m
B
A moves 2.5 m and B 2.5 m
C
A moves 3.5 m and B 2.5 m
D
A moves 2 m and B 4 m

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Text Solution

Verified by Experts
The correct answer is:
C

50 (3 + x) = 70 (3 – x)

150 + 50 x = 210 – 70x

120 x = 60

x = 0.5

for A, x A = 3 + 0.5

for B, x B = 3 – 0.5

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