A uniform meter scale balances at the 40 cm mark when weights of 10 g and 20 g are suspended from the 10 cm and 20 cm marks. The weight of the meter scale is –
Text Solution
Verified by ExpertsThe correct answer is:
C
τ lw = τ acw
Mg × 10 = 10 g × 30 + 20 g × 20
M = 70 gm.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A vessel containing water is given a constant acceleration a towards the right, along a straight ho…
A ship of mass initially at rest is pulled by a force of through a distance of 3 m. Assume that t…
The mass of a body measured by a physical balance in a lift at rest is found to be m. If the lift i…
Three weights W, 2W and 3W are connected to identical springs suspended from a rigid horizontal rod…
When forces are acting on a particle of mass m such that and are mutually perpendicular, then th…
The spring balance A reads 2 kg with a block m suspended from it. A balance B reads 5 kg when a bea…