If the lower block is held fixed and force is applied to P, minimum horizontal force required to slide P on Q is 12 N. Now if Q is free to move on frictionless surface and force is applied to Q, then the minimum force F required to slide P on Q is –
Text Solution
Verified by ExpertsThe correct answer is:
C
12 = μ 4g ⇒ μ = 0.3
a pmax possible = μ g = 3 m/s 2 F = (5 + 4) × 3 = 27 N
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