For the equilibrium of the system of a toy shown the relation between force F 1 and F 2 when the members are arranged to form three identical rhombuses is
A
F 1 = F 2
B
F 2 = 
C
F 2 = 
D
F 1 = 
Text Solution
Verified by ExpertsThe correct answer is:
D
Let AB = BC = CD = l unit and end A moves slightly towards right such that l is increased to (l + δ δ l).
Let the total work be zero, we get
F 1 3( δ δ l) – F 2 ( δ δ l) = 0
( Q displacement of A = 3 δ δ l and that of C is δ δ l)
or F 1 = 
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