The period of rotation of the earth so as to make any object weight-less on its equator is
Text Solution
Verified by ExpertsThe correct answer is:
A
Put g e = 0, in the expression
g e = g 0 - r ω ω 2 ⇒ ⇒ ω ω = 
⇒ ⇒ T = 2 π π 
, putting r = 6.4 × × 10 6 m and g 0 = 9.8 m/sec 2 ,
we obtain, T = 84 min
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