Particles of masses 2M, m and M are respectively at points A, B and C with AB=1/2(BC). m is much-much smaller than M and at time 
, they are all at rest as given in figure.
At subsequent times before any collision takes place
Text Solution
Verified by ExpertsThe correct answer is:
C
Force on B due to 
towards BA
Force on B due to 
towards BC
As, 
Hence, m will move towards 2M.
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