Two identical capacitors C 1 and C 2 of equal capacitance are connected as shown in the circuit. Terminals a and b of the key k are connected to charge capacitor C 1 using battery of emf V volt. Now, disconnecting 
and b the terminals b and c are connected. Due to this, what will be the percentage loss of energy? [NEET 2019]
Text Solution
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When C 1 is connected to voltage source, it is charged to a potential V and this will be stored as a potential energy in the capacitor given by
When key is disconnected from battery and b and c are connected, the charge will be transformed from the capacitor C 1 to capacitor C 2 , then
The loss of energy due to redistribution of charge is given by
Percentage loss 
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