If 
denotes the permittivity of free space and 
is the flux of the electric field through the area bounded by the closed surface, then dimensions of ( 
) are that of:
Text Solution
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We can use Gauss's law to analyze the dimensions. Gauss's law states that
,
where
is the electric flux,
q is the electric charge,
is the permittivity of free space.
To find the dimensions of 
, follow these steps:
Differentiate Gauss's law with respect to time:
Multiply the equation by 
:
Recognize that the time rate of change of charge, 
, is by definition the electric current.
Thus, the dimensions of 
are those of electric current.
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