The moment of inertia of a circular ring of mass M and diameter r about a tangential axis lying in the plane of the ring is:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
The moment of inertia of a circular ring with mass 
and diameter 
about a tangential axis lying in the plane of the ring is calculated as follows:
Given the diameter 
of the ring, the radius 
is 
.
The formula for the moment of inertia about a tangential axis in the plane of the ring is:
Substitute the value of 
into the equation:
Therefore, the moment of inertia of the ring about the specified axis is 
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A circular ring and a solid sphere having same radius roll down on an inclined plane from rest with…
If and represent the angular momentum and linear momentum respectively of a particle of mass ' '…
Which of the following are correct expression for torque acting on a body?
(A0
A solid sphere with uniform density and radius is rotating initially with constant angular velocit…
M and R be the mass and radius of a disc. A small disc of radius is removed from the bigger disc a…
A force of 49 N acts tangentially at the highest point of a sphere (solid) of mass 20 kg, kept on a…