A cube having a side of 10 cm with unknown mass and 200 gm mass were hung at two ends of a uniform rigid rod of 27 cm long. The rod along with masses was placed on a wedge keeping the distance between wedge point and 200 gm weight as 25 cm. Initially the masses were not at balance. A beaker is placed beneath the unknown mass and water is added slowly to it. At given point the masses were in balance and half volume of the unknown mass was inside the water.
(Take the density of unknown mass is more than that of the water, the mass did not absorb water and water density is 
.)
The unknown mass is ________ kg.
Text Solution
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(3)
Given, volume of block
Let density of block 
Buoyant Force
F.B.D. of blocks
Balancing torque about point O, we get
10 -2 )
Hence, mass of block 
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