Physics Thermometry, Thermal Expansion and Calorimetry JEE Main 2025 - ( Thermal Properties of Matter ) MCQ (Single Correct)

A 3 m long wire of radius 3 mm shows an extension of 0.1 mm when loaded vertically by a mass of 50 kg in an experiment to determine Young's modulus. The value of Young's modulus of the wire as per this experiment is , where the value of P is: (Take )

A
2.5
B
25
C
10
D
5

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Text Solution

Verified by Experts
The correct answer is:
D

Let's break down the solution step by step:

First, note the given values:

Length of the wire,
Radius of the wire,

Extension of the wire,

Mass attached,
Acceleration due to gravity,

The force (weight) acting on the wire is:

Next, calculate the cross-sectional area, A, of the wire:

Young's modulus, E, is given by:

Substitute the values into the formula:

Simplify step by step:
Multiply in the numerator:

Multiply in the denominator:

Cancel the common factor in the numerator and denominator:

Divide 450 by 9:

The problem states that Young's modulus can be expressed as . Here we have:

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