A square current carrying loop 
is placed near an infinitely long another current carrying wire ef. Now, match the Column I with Column II and mark the correct option from the codes given below.
Column I | Column II | ||
A. | Net force on bc and da | I. | zero |
B. | Net force on ab and cd | II. | non-zero and unequal |
C. | Net force on complete loop abcd | III. | rightwards |
D. | Net force on ef | IV. | leftwards |
Choose the correct answer from the options given below.
Text Solution
Verified by ExpertsD
Magnetic field over the loop due to straight wire is perpendicular to paper inwards.
Force, 
Force on bc is equal to force and on da hence, net force is zero.
Distance of ab from ef is not same as distance of cd from ef hence, net force is non-zero and unequal.
According to the above explanation, net force on 
is leftward because force on 
is greater than cd.
According to Newton's third law, force on ef will be rightward.
Hence, A-I, B-II, C-IV, D-III.
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