The pitch of the screw gauge is
and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while 72 nd division on circular scale coincides with the reference line. The radius of the wire is:
Text Solution
Verified by ExpertsThe correct answer is:
B

zero error
True reading (Diameter)




therefore, radius
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In your laboratory what you will prefer for measuring thickness of a resistance wire for specific r…
Using the ratchet of a screw gauge, the screw should be rotated in same direction to avoid :-
Backlash error corresponds to :-
The incorrect statement is :-
For the pitch of a screw and 200 divisions on circular scale, the least count will be :-
The screw gauge has least count of and its circular scale is divided into 100 equal divisions. Wha…