A beam of light contains two wavelengths 
and 
. They form interference fringes in Young's double slit experiment. What is the least distance (approx) from central maxima, where the bright fringes due to both wave length coincide? The distance between the slits is 2 mm and distance between the screen and slit is 120 cm.
Text Solution
Verified by ExpertsA
To find the point of coincidence of bright fringes, we can equate the distance of bright fringes from the central maximum, made by both the wavelengths of light.
Given, distance between the screen and slit,
Slit width, 
Let 
th fringe due to 
coincide with 
th bright fringe due to 
.
= 5
So, the least distance required, 
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