As shown in the figure, P and Q are two co-axial conducting loops separated by some distance. When the switch S is closed, a clockwise current I P flows in P (as seen by E) and an induced current I Q1 flows in Q. The switch remains closed for a long time. When S is opened, a current I Q2 flows in Q. Then, the directions of I Q1 and I Q2 (as seen by E) are

Text Solution
Verified by ExpertsD
When switch S is closed, then magnetic field lines passing through Q increases in the direction from right to left.
So, according to Lenz's law, induced current in Q, i.e. I Q1 will flow in such a direction, so that the magnetic field lines due to I Q1 passes from left to right through Q. This is possible when I Q1 flows in anti-clockwise direction as seen by E. Opposite is the case when switch
is opened, i.e. I Q2 will be clockwise as seen by E.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems