Consider an optical communication system operating at λ λ ~800 nm . Suppose, only 1% of the optical source frequency is the available channel bandwidth for optical communication. How many channels can be accommodated for transmitting audio signals requiring a bandwidth of 8 kHz
Text Solution
Verified by ExpertsThe correct answer is:
A
Optical source frequency 
= 3 × × 10 8 /(800 × × 10 –9 ) = 3.8 × × 10 14 Hz
Bandwidth of channel (1% of above) = 3.8 × × 10 12 Hz
Number of channels =(Total bandwidth of channel)/ (Bandwidth needed per channel)
Number of channels for audio signal
~ 4.8 × × 10 8
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