The displacement of a particle, executing simple harmonic motion with time period
, is expressed as
, where
is the amplitude. The maximum value of potential energy of this oscillator is found at
. The value of
is
.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(2) For SHM with
, the potential energy is
.
Maximum potential energy occurs when
, i.e., when
The first maximum occurs at
, giving
.
Since this is given as
.
We have
, so
.
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