Home Physics Thermodynamics JEE Main 2026 The internal energy of a monoatomic gas is 3…
Physics Thermodynamics JEE Main 2026 MCQ (Single Correct)

The internal energy of a monoatomic gas is 3 nRT . One mole of helium is kept in a cylinder having internal cross section area of and fitted with a light movable frictionless piston. The gas is heated slowly by suppling 126 J heat. If the temperature rises by , then the piston will move cm . (atmospheric pressure )

A
1.45
B
15.5
C
1.55
D
14.5

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Text Solution

Verified by Experts
The correct answer is:
B

The question states the internal energy of the gas is .

The change in internal energy is .
Given: mole, , and .
.
According to the first law of thermodynamics, .
Given heat supplied .
Work done by the gas .
Since the piston is light and movable, the process occurs at constant atmospheric pressure .
Work done , where is the cross-section area and is the displacement of the piston.
.
.
.
.
Converting to .
Rounding to the nearest option, we get 15.5 cm .

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