A particle of charge Q and of negligible initial speed is accelerated through a potential difference of U. The particle reaches a region of uniform magnetic field of induction B, where it undergoes circular motion. If potential difference is doubled and B is also doubled then magnetic moment of the circular current due to circular motion of charge Q will become.
Text Solution
Verified by ExpertsThe correct answer is:
A
K.E = QU magnetic moment = i × Area = 
× πR 2
∴ T = 
R = 
= 
Magnetic moment = 
× 
Magnetic moment = QU
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