A bar magnet with it's poles 25 cm apart and of pole strength 24 amp × × m rests with it’s Centre on a frictionless pivot. A force F is applied on the magnet at a distance of 12 cm from the pivot so that it is held in equilibrium at an angle of 30° with respect to a magnetic field of induction 0.25 T. The value of force F is
Text Solution
Verified by ExpertsThe correct answer is:
D
In equilibrium
Magnetic torque 
Deflecting torque
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