The maximum intensity in Young's double slit experiment is I 0 . Distance between the slits is d = 5 λ λ , where λ λ is the wavelength of monochromatic light used in the experiment. What will be the intensity of light in front of one of the slits on a screen at a distance 
A
B
C
I 0
D
Text Solution
Verified by ExpertsThe correct answer is:
A
Suppose P is a point infront of one slit at which intensity is to be calculated from figure it is clear that 
. Path difference between the waves reaching at P
Hence corresponding phase difference 
Resultant intensity at P
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