The dimensions of
, where e, ε 0 , h and c are electronic charge, electric permittivity, Planck’s constant and velocity of light in vacuum respectively is -
Text Solution
Verified by ExpertsThe correct answer is:
A

[
= F ⇒ ke 2 = Fr 2 Energy E =
⇒ hc = E λ]
= [M
0 L 0 T 0 ]
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