In a particular system, the unit of length, mass and time are chosen to be 10 cm, 10g and 0.1s respectively. The unit of force in this system will be equivalent to -
Text Solution
Verified by ExpertsThe correct answer is:
A
n 1 u 1 = n 1 u 2
Let 1 dyne = nu
Where u = new unit of force[F] = [M 1 L 1 T –2 ]
1 gm. cm.s –2 = n.(10gm) . (10cm) . (0.1s) –2 where 10 gm, 10 cm are 0.1 s are new units of mass, length and time respectively
solving the above relation we get n = 10
–4 i.e. 1 dyne = 10
–4 u
or 10 –5 newton = 10 –4 u
or 
Newton
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