A block of mass 5 kg is suspended by a mass less rope of length 2 m from the ceiling. A force of 50 N is applied in the horizontal direction at the midpoint P of the rope, as shown in the figure:
The angle made by the rope with the vertical in equilibrium is (Take 
)
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
: let 
be the angle made by rope with the vertical in equilibrium
The free body diagram of 5 kg block is as shown in fig
In equilibrium 
The free body diagram of the point p is as shown in fig
In equilibrium 
Dividing (i) by (ii) we get
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