Two sitar strings A and B are slightly out of tune and produce beats of frequency 5 Hz. When the tension in the string B is slightly increased, the beat frequency is found to reduce to 3 Hz. If the frequency of string A is 427 Hz, the original frequency of string B is
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The frequency of string A,
Let original frequency of string B be 
.
= 432 Hz or 422 Hz
Increase in the tension of a string, B increase its frequency
(i) If 
a further increase in 
increases the beat frequency. But this is not given in the questions.
(ii) If 
a further increase in 
decreases the beat frequency. This is given in the equations.
The original frequency of strings B is 422 Hz.
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