A P 32 radio nuclide with half life T = 14.3 days is produced in a reactor at a constant rate q = 2.7 × 10 9 nuclei per second. How soon after the beginning of production of that nuclide will its activity be equal to A = 1.0 × 10 9 dis./s?
Text Solution
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Sol. According to the problem, the radio nuclide is being produced at a constant rate as well as it decay with rate – 
= λ N. Hence net rate of accumulation of radio nuclide is given by
= q – λ N or 
= 
or – 
= t
or – 
ln 
= t
or t = 
ln 
where λ = 
and A = λ N
On substituting numerical values, we get
t = 9.5 days
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