A nucleus at rest undergoes a decay emitting an α - particle of de-Broglie wavelength λ = 5.76 × 10 –15 m. If the masses of daughter nucleus is 223.610 amu and that of the α - particle is 4.002 amu, determine the total kinetic energy in the final state. Hence, obtain the mass of the parent nucleus in amu. (1 amu = 931.5 MeV/c 2 )
Text Solution
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Sol. de Brogile wavelength of 
-particles, 
de Broglie wavelength, 
Therefore, momentum of 
-particle,
If 
is momentum of daughter nucleus, then from coservation of linear momnetum,
Hence, total kinetic of final state,
Therefore, total kinetic energy of final state is
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