A cubical block of glass (refractive index µ = 1.5) has a concentric spherical cavity of radius r = 3 cm. Each edge of the cube is l = 12 cm log. A luminous point object is at a distance a = 12 cm on left of left face of the cube as shown in Fig. Calculate apparent position of the object when seen from right side of the cube.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Sol. Let us consider individual events involved in image formation
(i) Refraction at plane surface (Air/glass interface)
Using 
= 
, we get
= 
⇒ v 1 = – 18 cm
A virtual image is formed on the left of left plane face which will act as object for the next interface.
(ii) Refraction at curved surface (glass/Air interface)
Using 
– 
= 
, we get
– 
= 
⇒ v 2 = – 4.2 cm
A virtual image is formed which will work as object for next event.
(iii) Refraction at curved surface (Air/Glass interface)
– 
= 
⇒ v 3 = – 
cm
The image formed is virtual and it is left of interface. This will act as object for refraction at right plane face.
(iv) Refraction at plane surface (Glass/Air interface)
= 
⇒ v 4 = – 
cm
∴ Distance of final image is 
cm from right face towards left.
– 
= 
… (3)
– 
= 
… (4)
Adding (3) and (4), we get
– 
= 
[0.3 – 0.1] = 
= 
= 
– 
⇒ v 2 = 
cm.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems