In the YDSE apparatus shown in figure Δ x is the path difference between S 2 P and S 1 P. Now a glass slab is introduced in front of S 2 , then match the following –
Column-I | Column-II |
(i) Δx at P will | [A] Increase |
(ii) Fringe width will | [B] shift downward |
(iii) Fringe pattern will | [C] remain same |
(iv) Number of fringes between O and P will | [D] shift upward |
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Ans.
(i) [A]
(ii) [C]
(iii) [B]
(iv) [C]
Sol. If glass slab is introduced across S 2 this effective path increases so central maxima will be shifted downward but fringe width remains same.
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