A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1 m behind the front axle. The force exerted by the level ground on each front wheel and each back wheel is (Take g= 10 m s-2)
Text Solution
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Here, mass of the car, M = 1800 kg
Distance between front and back axles = 
distance of gravity G behind the front axle = 1 m
Let 
and 
be the forces exerted by the level ground on each front wheel and each back wheel. 
For translational equilibrium.
Or 
…. (i)
As there are two front wheels and two back wheels For rotational equilibrium about G
( 
(1) = ( 
) ( 
)
….. (ii)
Substituting this in Eq. (i), we get
)
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