A wire frame AOPQB is free to rotate about a vertical axis passing through C ⊥ ⊥ to plane of AOPQB. The mass M of the frame is uniformly distributed over its whole length. What is the moment of inertia of the frame about this axis, if OA = QB = r and CP = r (the radius of semicircular part )
A
Mr 2 
B
Mr 2 
C
Mr 2 
D
Mr 2
Text Solution
Verified by ExpertsThe correct answer is:
A
M.I. = M.I. of OA + M.I of Q.B. + M.I. of semicircular region
= 2 
2 ⋅ ⋅ 
= Mr 2 
is the correct.
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