A train accelerates from rest for time t1, at a constant acceleration α for distance x. Then it decelerates to rest at constant retardation β in time t2 for distance y. Then -
A
= 
B
= 
C
= 
D
x = y
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION
(a, b ,c) In accelerated motion
v = α t 1
and v 2 = 2 α x
when decelerates
0 = v – β t 2
or α t 1 = β t 2
⇒ 
= 
0 = v 2 – 2 β y
v 2 = 2 β y
or 2 α x = 2 β y
⇒ 
= 
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