A ball is thrown form the top of a tower with an initial velocity of 10 m s -1 at an angle of 
with the horizontal. If it hits the ground of a distance of 17.3 m from the back of the tower, the height of the tower is (Take g = 10 m s -2 ).
Text Solution
Verified by ExpertsThe correct answer is:
D
Here, 
For horizontal motions, 
Or 
For vertical motions, y 
= 10- 20 = -10 m.
Height of tower = 10m.
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