A small block slides with velocity 0.5 √ √ gr on the horizontal frictionless surface as shown in Fig. The block leaves the surface at L. The angle α α is
A
cos -1 
B
cos -1 
C
sin -1 
D
sin -1 
Text Solution
Verified by ExpertsThe correct answer is:
A
Here cos α α = 
or -h = r cos α α - r
or h = r(1 – cos α α )
At L, mg cos α α = 
= 
or mg cos α α = 
= 
or cos A = 
+ 2 – 2 cos α α
or 3 cos α α = 
or cos α α = 
or α α = cos -1 
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