A wire of fixed length is turned to form a coil of one turn. It is again turned to form a coil of three turns. If in both cases same amount of current is passed, then the ratio of the intensities of magnetic field produced at the centre of a coil will be
times of first case
times of first case
Text Solution
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Magnetic field at the centre of n turn coil carrying current i
......(i)
For single turn n =1
.....(ii)
If the same wire is turn again to form a coil of three turns i.e. n = 3 and radius of each turn 
So new magnetic field at center
⇒ ⇒ 
......(iii)
Comparing equation (ii) and (iii) gives 
.
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