A length L of wire carrying current I is bent into a circle of one turn. The field at the center of the coil is B 1 . A similar wire of length L carrying current I is bent into a square of one turn. The field at its center is B 2 . Then-
Text Solution
Verified by ExpertsThe correct answer is:
B
Magnetic field due to circle
B 1 = 
but L = 2 π R ⇒ 2R = 
⇒ B 1 = 
3.14 
Magnetic field due to square coil B 2 = 
but L = 4x ⇒ x = 
∴ B 2 = 
3.60 
∴ B 1 < B 2
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