Calculate the magnetic moment of a thin wire with a current I = 0.8 A, wound tightly on half a tore (Fig.
A
). The diameter of the cross-section of the tore is equal to d = 5.0 cm, the number of turns is N = 500. 
Fig.
Fig.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. We consider a differential element making angle d θ at O.
Fig.
Fig.
The number of turns in the considered element is
dN = 
d θ
dP m = dNIS = dNI 
From Fig. , where s-cross sectional area
d 
= d μ m cos θ 
– d μ m sin θ 
μ mx = 
d μ m sin θ
= – 
sin θ = – 
sin θ d θ
= – 
d θ = 
= 
[cos π – cos 0] = – 
Similarly, μ my = 
cos θ d θ = 
= 0
μ m = μ mx = 
= 0.5 Am 2 .
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Magnetic effect of current was discovered by
The direction of magnetic lines of forces close to a straight conductor carrying current will be
The ratio of the magnetic field at the centre of a current carrying coil of the radius a and at a d…
“On flowing current in a conducting wire the magnetic field produces around it.” It is a law of
A circular current carrying coil has a radius R. The distance from the center of the coil on the ax…
The field normal to the plane of a wire of n turns and radius r which carries a current i is measur…