A sliding rod AB of resistance R is shown in the figure. Here magnetic field B is constant and is out of the paper. Parallel wires have no resistance and the rod is moving with constant velocity v. The current in the sliding rod AB when switch S is closed at time t = 0 is
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Here magnetic field 
is constant and is out of paper.
When the sliding rod AB moves with a velocity in the direction shown in figure, the induced current in AB is from A to B.
As the switch S is closed at time t = 0 the capacitor gets charged.
If q is the charge on the capacitor, then
or 
Or 
(where A is a constant ….. (i)) At t = 0, q = 0
From (i) q = vBdC 
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