Particles of masses 2M, m and M are respectively at points A, B and C with AB = 1/2 (BC). m is much-much smaller than M and at time t = 0, they are all at rest. At subsequent times before any collision takes place
Text Solution
Verified by ExpertsThe correct answer is:
C
Force on mass m at B due to mass 2M at A is
Force on mass m at B due to mass M at C is
resultant force on mass m at B due to masses at A and C is
are acting in opposite directions
Therefore, m will move towards 2 M.
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