Consider a particle of mass m on the axis of a ring of mass M & radius r, at a distance r from the centre of ring, this particle moving under the gravitational attraction of the ring, reaches the centre of the ring. The velocity of the particle at the centre of the ring will be -
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
Gravitational P.E. = 
(T.E.) A = (T.E.) B
Let velocity at B is V so
K.E. + P.E. = constant
0 + 
= 
mv 2 + 
v = 
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