A very very large number of particles of same mass m are kept at horizontal distances of 1m, 2m, 4m, 8m and so on from (0,0) point. The total gravitational potential at this point is (addition of G.P. of infinite terms =
where a = first term, r = common ratio)
Text Solution
Verified by ExpertsThe correct answer is:
D

v = v1 + v2 + v3 + v4 + ......
= –
–
–
–
–
–
– ........
= – Gm
→ G.P. of infinite series
= – Gm 
v = – Gm = – 2Gm
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