A brass rod of length 2 m and cross-sectional area 2.0 cm 2 is attached end to end to a steel rod of length L and cross-sectional area 1.0 cm 2 . The compound rod is subjected to equal and opposite pulls of magnitude 5 × 10 4 N at its ends. If the elongations of the two rods are equal, then length of the steel rod (L) is
(Y Brass = 1.0 × 10 11 N/m 2 and Y Steel = 2.0 × 10 11 N/m 2 )
Text Solution
Verified by ExpertsThe correct answer is:
D
Since the elongation of the two rods are equal
ог 
or 
The length of the steel rod
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