A 2m long light metal rod AB is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One wire is of brass and has cross-sectional area of 0.2 × 10 –4 m 2 and the other is of steel with 0.1 × 10 –4 m 2 cross-sectional area. in order to have equal stresses in the two wires, a weight W is hung from the rod. The position of the weight along the rod from end A should be
Text Solution
Verified by ExpertsThe correct answer is:
A
A B = 0.2 × 10 –4
A S = 0.1 × 10 –4
F 1 + F 2 = mg
.....
F 1 x = F 2 (2–x) ......
x = 
= 66.6 cm
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