A stone projected vertically up with a velocity u reaches a maximum height h. When it is at a height of 3h/4 from the ground, the ratio of KE and PE at that point is: (consider PE = 0 at the point of projector)
Text Solution
Verified by ExpertsThe correct answer is:
C
mu 2 = mgh, u 2 = 2gh....(i)
mg 
+ K.E. = mgh
K.E. = 
= 
= 
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