Two equal masses are attached to the two ends of a spring of spring constant k. The masses are pulled out symmetrically to stretch the spring by a length x over its natural length. The work done by the spring on each mass during the above pulling is
A
kx 2
B
– 
kx 2
kx 2
C
kx 2
D
– 
kx 2
kx 2
Text Solution
Verified by ExpertsThe correct answer is:
D
W 1 = work done by spring on first mass
W 2 = work done by spring on second mass
W 1 = W 2 = W (say)
W 1 + W 2 = U i – U f
2W = 0 – 
Kx 2
W = – 
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