An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg. The mass of the elevator itself is 920 kg and it moves with a constant speed of 3 m/s. The frictional force opposing the motion is 6000 N. If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator (g = 10 m/s 2 ) must be at least:
Text Solution
Verified by ExpertsThe correct answer is:
D
Net force on motor will be
F m = [920 + 68(10)] g + 6000
= 22000 N
So, required power for motor
P m = 
. 
= 22000 x 3
= 66000 watt
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