Two unequal soap bubbles are formed one on each side of a tube closed in the middle by a tap. What happens when the tap is opened to put the two bubbles in communication?
Text Solution
Verified by ExpertsThe correct answer is:
C
P A = P 0 + 
; P B = P 0 + 
{P 0 = atmospheric pressure}.
Clearly P A > P B ; so air will flow from A to B.
As r decreases; pressure will become more and hence more flow of air from A to B.
Ultimately bubble A collapses and B becomes bigger in size.
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