The work done to get n smaller equal size spherical drops from a bigger size spherical drop of water is proportional to:
A
B
C
n 1/3 – 1
D
n 4/3 – 1
Text Solution
Verified by ExpertsThe correct answer is:
C
conserving volume
n × 
π r 3 = 
π R 3 ......(i) { volumes are equal}.
and Δ A = – [4 π R 2 – n.4 π r 2 ]
where W = ( Δ A) × T.
= –4 π [n 2/3 r 2 – n.r 2 ] × T = 4 π r 2 T. n 2/3 [n 1/3 –1].
Now R 2 = n 2/3 . r 2
so W = 4 π R 2 T [n 1/3 – 1].
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